A train leaves Station A at 08:00 and travels at 80 km/h. Another train leaves Station B at 09:00 and travels towards Station A at 100 km/h. The distance between stations is 400 km. At what time will they meet?

Jawaban: 10:30

First train has 1-hour head start: distance = 80 km. Remaining distance = 400−80 = 320 km. Combined speed = 80+100 = 180 km/h. Time to meet = 320/180 = 1.777... hours = 1 hour 46.67 min, so about 10:46. Not matching options. Adjust: If first train leaves at 08:00, second at 09:00, distance 400, speeds 80 and 100. They meet at 08:00 + t hours for first, 09:00 + (t−1) hours for second. 80t + 100(t−1) = 400 → 180t − 100 = 400 → 180t = 500 → t = 2.777... hours = 2h 46.67m → 10:46. Not 10:30. To get 10:30, t=2.5 hours: 80×2.5 + 100×1.5 = 200+150=350 ≠ 400. So not. I will change numbers: distance 36