A train leaves Station A at 9:00 a.m. and travels at 60 km/h. Another train leaves Station B at 10:00 a.m. and travels towards Station A at 80 km/h. The distance between stations is 300 km. At what time will they meet?

Jawaban: 11:30 a.m.

By 10 a.m., first train has traveled 60 km, leaving 240 km between them. Their combined speed is 140 km/h, so they meet after 240/140 = 1.71 hours ≈ 1 hour 43 minutes, so around 11:43 a.m. But options are limited. Let's calculate precisely: 240/140 = 12/7 hours = 1 hour 42.86 min, so about 11:42:51, which is closest to 11:30? Actually 11:30 is 1.5 hours after 10, which would be 210 km covered, not 240. So none match exactly. Maybe I made a mistake. Let's recalc: At 10 a.m., first train has traveled 1 hour * 60 = 60 km. So distance left = 300-60=240 km. Combined speed = 60+80=140 km/h. Time to