A train leaves Station A at 9:00 AM traveling at 60 km/h. Another train leaves Station B, 300 km away, at 10:00 AM traveling towards Station A at 80 km/h. At what time will they meet?

Jawaban: 12:00 PM

By 10:00 AM, first train traveled 60 km, remaining distance 240 km. Relative speed 140 km/h. Time to meet = 240/140 = 12/7 hours ≈ 1 hour 43 min. So they meet at 11:43 AM, not exactly. So adjust numbers: if distance 300, first train 60, second 80, leave at 9 and 10, then by 10:00 first traveled 60, remaining 240, time=240/(60+80)=240/140=1.714h=1h43m, meet at 11:43. Not in options. So change: if first leaves at 8:00, second at 9:00, then by 9:00 first traveled 60, remaining 240, time=240/140=1.714h, meet at 10:43. Not. So maybe use 300 km, first at 60, second at 90, leave at 9 and 10: by 10:00