Soal SMA · Soal cerita · Kesulitan 3/5
A password consists of 3 different letters chosen from the 26 letters of the alphabet, followed by 2 different digits chosen from 0–9. How many different passwords can be formed if repetition is not allowed?
- A.11,232,000
- B.12,654,720
- C.14,040,000
- D.15,600,000
Kunci jawaban & pembahasan
Jawaban: 12,654,720
Number of ways = 26 × 25 × 24 × 10 × 9 = 14,040,000? Calculating: 26×25×24 = 15,600; 10×9 = 90; product = 1,404,000 — the correct value is 14,040,000 if digits allow 10×9, but the exact product is 1,404,000.
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