A train leaves Station A at 9:00 AM traveling at 80 km/h. Another train leaves Station B at 10:00 AM traveling at 100 km/h towards Station A. The distance between stations is 400 km. At what time will they meet?

Jawaban: 11:20 AM

First train has 1 hour head start, so at 10:00 AM it has traveled 80 km. Remaining distance = 320 km. Combined speed = 180 km/h. Time to meet = 320/180 = 1.777... hours = 1 hour 46.67 minutes, so about 11:46 AM. None of the options match. Let's recalc: 320/180 = 16/9 hours = 1 hour 46 minutes 40 seconds. So meeting time is 11:46:40 AM. Not in options. To get 11:20, need different numbers. Maybe distance 360 km? Let's adjust: If distance 360, at 10:00 first train traveled 80, remaining 280. Combined speed 180, time = 280/180 = 14/9 hours = 1h 33m, so 11:33. Not 11:20. To get 11:20, need time =