Soal SMA · Soal cerita · Kesulitan 3/5
A chemist has a 20% saline solution and a 50% saline solution. How many liters of the 50% solution must be added to 30 liters of the 20% solution to obtain a 30% saline solution?
- A.10 liters
- B.15 liters
- C.20 liters
- D.25 liters
Kunci jawaban & pembahasan
Jawaban: 15 liters
Let x = liters of 50% solution. Salt from 20% = 0.20×30 = 6. Salt from 50% = 0.50x. Total salt = 6 + 0.5x. Total volume = 30 + x. Want 30%: (6+0.5x)/(30+x) = 0.30. 6+0.5x = 9 + 0.3x → 0.2x = 3 → x = 15. Correct.
Mau penjelasan yang menyesuaikan level anak?
Xinau AI membahas soal langkah demi langkah, menyesuaikan gaya bahasa dengan usia anak, dan menyusun latihan berikutnya berdasarkan jawaban sebelumnya.
Coba gratis 30 hari