A box contains 24 marbles: 8 red, 6 blue, and 10 green. If 3 marbles are drawn at random without replacement, what is the probability that all three are green?

Jawaban: 1/6

Probability = (10/24) × (9/23) × (8/22) = (10×9×8)/(24×23×22) = 720/12144 = 15/253 ≈ 0.059, which is not 1/6. This is incorrect. Let me recalculate: 10/24 × 9/23 × 8/22 = (10*9*8)/(24*23*22) = 720/12144 = 60/1012 = 15/253 ≈ 0.0593, not among options. So I will change the question to something simpler: A bag contains 5 red, 3 blue, 2 green. Probability of drawing a red or blue? Total=10, red or blue=8, probability=0.8. But that is similar to earlier. I will instead ask: A box contains 4 red, 6 blue, and 5 green marbles. If one marble is drawn, what is the probability that it is not red? Total=1