A train leaves Station A at 09:00 traveling at 60 km/h. Another train leaves Station B at 09:30 traveling towards A at 80 km/h. If the distance between stations is 260 km, at what time do they meet?

Jawaban: 11:00

By 09:30, first train covers 30 km. Remaining = 230 km. Relative speed = 140 km/h. Time = 230/140 = 1.6428 h ≈ 1h38.6m, so meet around 11:08. However, exact calculation: 230/140=1.642857h=1h38m34s, so 09:30+1h38m=11:08. Closest option is 11:00? Re-evaluate: 230/140=1.6428h=1h38.57m, so 11:08:34. None match exactly. Adjust numbers: Let distance be 250 km. Then by 09:30, first train covers 30 km, remaining 220 km. Relative speed 140 km/h. Time = 220/140=1.5714h=1h34.28m, meet at 11:04:17. Still not matching. Let's use 240 km: remaining 210 km, time=210/140=1.5h=1h30m, meet at 11:00. So change di